The numerical value of charge on either plate of capacitor C shown in figure is

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\frac{C E R_{1}}{R_{1} + r}

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\frac{C E R_{2}}{R_{2} + r}

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\frac{C E R_{1}}{R_{2} + r}

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Solution

The correct option is B $\frac{C E R_{1}}{R_{1} + r}$
A fully charged capacitor no current draws from source. So no current flow in the capacitor branch and current flow through $R_{1}$ and r.
Thus, the current in circuit , $I = \frac{E}{R_{1} + r}$
here, Potential across capacitor $V_{c} =$ potential across $R_{1} = I R_{1} = \frac{E}{R_{1} + r} R_{1}$
Charge on capacitor $= C V_{c} = C \frac{E}{R_{1} + r} R_{1}$

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