Question

The numerical value of $\frac{9}{cose{c}^2\theta }+4co{s}^2\theta +\frac{5}{1+ta{n}^2\theta }$ is

• A. $4$
• B. $5$
• C. $9$
• D. $1$

Answer 1

Answer: (C)

$9$

$\frac{9}{cose{c}^2\theta }+4co{s}^2\theta +\frac{5}{1+ta{n}^2\theta }$
$9si{n}^2\theta +4co{s}^2\theta +\frac{5}{se{c}^2\theta }$
$9si{n}^2\theta +4co{s}^2\theta +5co{s}^2\theta$
$9si{n}^2\theta +9co{s}^2\theta$
$9(si{n}^2\theta +co{s}^2\theta )=9\times 1=9$