Question

The numerical value of energy involved in the given process $K\to K^{-}$ is less than that of which of the following processes ?

• A. $K^{-}\to K$
• B. $K\to K^{+}$
• C. Both (a) and (b)
• D. None of these

Answer 1

The correct option is B $K\to K^{+}$

$K\to K^{-}$ is on exothermic process, i.e., the energy involved has -ve value.
$K^{-}\to K$ is opposite of $K\to K^{-}$ .
$\therefore$ Numberical value would be the same but sign will be opposite. But $K\to K^{+}$ is I.E. of K.
$\therefore$ It is higher than the above process as it is a having a positive value.