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Question

The numerical value of middle terms in (1−1x)n(1−x)n is

A
2nCn
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B
nCn
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C
(2nCn)
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D
(nCn)
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Solution

The correct option is A 2nCn
(11x)n(1x)n

=(x1)nxn(1x)n

=(1)nxn(1x)2n

middle term = Tn+1=(1)nxn.2nCn(1)2nn(x)n

=(1)nxn.2nCn.1.(1)n.xn

middle term = (1)2n.2nCn

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