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Byju's Answer
Standard XII
Physics
Image in Thin Lens by Ray Tracing
The objective...
Question
The objective of an astronomical telescope has a focal length of
100
cm
. The telescope is focused for normal vision of distant objects when tube length is
1.1
m
. Find magnifying power of the telescope.
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Solution
Given,
Focal length of objective,
f
o
=
100
cm
Length of objective,
L
=
1.1
m
=
110
cm
In case of normal adjustment,
L
=
f
o
+
f
e
⇒
110
=
100
+
f
e
∴
f
e
=
10
cm
Now, magnifying power,
m
=
∣
∣
∣
−
f
o
f
e
∣
∣
∣
=
100
10
=
10
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