The observer is moving with velocity $^{'} v_{0}^{'}$ towards the stationary source of sound and then after crossing moves away from the source with velocity $^{'} v_{0}^{'}$ . Assume that the medium through which the sound waves travel is at rest. If $^{'} v^{'}$ is the velocity of sound and $^{'} n^{'}$ is thee frequency emitted by the source then the difference between apparent frequencies heard by the observer is

\frac{2 n v_{0}}{v}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{n v_{0}}{v}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{v}{2 n v_{0}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{v}{n v_{0}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{2 n v_{0}}{v}$
Using doppler effect formula
Case I : Observes approaching the source.
$V^{1} = (\frac{V + V_{o}}{V}) n$ .... (I)
Case II : Observes moving away from the source
$V^{1} = (\frac{V - V_{o}}{V}) n$ .... (II)
Different between 2 frequencies
$(I) - (I I) = \frac{2 V_{o} n}{V}$

Suggest Corrections

Similar questions

Q. If a source emitting waves of frequency

f

moves towards an observer with a velocity

\frac{v}{4}

and the observer moves away from the source with a velocity

v / 6

, the apparent frequency as heard by the observer will be (

v =

velocity of sound)

Q. When the observer moves towards the stationary source with velocity, 'V

_{1}

', the apparent frequency of emitted note is 'F

_{1}

'. When the observer moves away from the source with velocity 'V

_{1}

', the apparent frequency is 'F

_{2}

'. If 'V' is the velocity of sound in air and

\frac{F_{1}}{F_{2}} = 2

then,

\frac{V}{V_{1}}

Q. A source of sound emitting a tone of frequency 200 Hz moves towards an observer with a velocity v equal to the velocity of sound. If the observer also moves away from then source with the same velocity v, the apparent frequency heard by the observer is

A source of sound emitting a note of frequency 200 Hz moves towards an observer with a velocity $v$ equal to the velocity of sound. If the observer also moves away from the source with the same velocity $v$ , the apparent frequency heard by the observer is

A source of sound emitting a note of frequency 200 Hz moves towards an observer with a velocity v equal to the velocity of sound. If the observer also moves away from the source with the same velocity v, the apparent frequency heard by the observer is

Join BYJU'S Learning Program

The correct option is A 2nv0vUsing doppler effect formulaCase I : Observes approaching the source.V1=(V+VoV)n .... (I) Case II : Observes moving away from the sourceV1=(V−VoV)n .... (II) Different between 2 frequencies(I)−(II)=2VonV