The octahedral complex of a metal ion $M^{3 +}$ with four monodentate ligands $L_{1}, L_{2}, L_{3} a n d L_{4}$ absorb wavelengths in the region of red, green, yellow and blue, respectively. The increasing order of ligand strength of the four ligands is
(IIT-JEE, Advanced 2014)

L_{3} < L_{2} < L_{4} < L_{1}

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L_{1} < L_{2} < L_{4} < L_{3}

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L_{4} < L_{3} < L_{2} < L_{1}

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L_{1} < L_{3} < L_{2} < L_{4}

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Solution

The correct option is D $L_{1} < L_{3} < L_{2} < L_{4}$
This is a very interesting question. This has to do with VBT and CFT ideas. See, strong field ligands cause higher magnitude of crystal field splitting which is accompanied by the absorption of higher energy radiation. It is that simple! High energy refers to higher frequency since $E = h ν$ . What colour has the highest frequency? Blue! Well technically - violet right? Hence this makes sense: $V I B G Y O R \to$ decreasing energy.

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A: y = 2

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