The octet rule is not followed by:

F_{2}

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N a F

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C a F_{2}

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B F_{3}

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Solution

The correct option is D $B F_{3}$
The octet rule is not followed by ${B F}_{3}$
Boron has less than 4 outer electrons. Even if all the outer electrons are used to form bonds, an octet cannot be attained.

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