Question

The odds in favour of $A$ winning a game of chess against $B$ are $5:2$. If three games are to be played, then the odds in favour of A's winning at least one game are $355:8$. If this is true enter 1, else enter 0.

Answer 1

We have $p=1-{\left(\frac{2}{7}\right)}^3=\frac{335}{343}.$ Hence odds in favour are as $335:343-335$ or $335:8$.