The odometer of a car reads $57321.0$ km when the clock shows the time $08 : 30$ AM. What is the distance moved by the car, if at $08 : 50$ AM, the odometer reading has changed to $57336.0$ km $?$ Calculate the speed of the car in km $/$ min during this time. Express the speed in km $/$ h also.

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Solution

Distance $= 57336.0 k m - 57321 k m = 15 k m$
Speed in km $/$ min $= 15 k m / 20 m i n = \frac{3}{4} k m / m i n$
Speed in $k m / h r = \frac{3}{4} \times \frac{k m}{m i n} \times \frac{60 m i n}{h r} = (15 \times 3) k m / h r = 45 k m / h r$ .

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The odometer of a car reads 57321.0km when the clock shows the time 08:30AM. What is the distance moved by the car, if at 08:50 AM, the odometer reading has changed to 57336.0km ? Calculate the speed of the car in km/min during this time. Express the speed in km/h also.

Distance =57336.0km−57321km=15kmSpeed in km/min =15km/20min=34km/minSpeed in km/hr=34×kmmin×60minhr=(15×3)km/hr=45km/hr.

The odometer of a car reads $57321.0$ km when the clock shows the time $08 : 30$ AM. What is the distance moved by the car, if at $08 : 50$ AM, the odometer reading has changed to $57336.0$ km $?$ Calculate the speed of the car in km $/$ min during this time. Express the speed in km $/$ h also.

Distance $= 57336.0 k m - 57321 k m = 15 k m$
Speed in km $/$ min $= 15 k m / 20 m i n = \frac{3}{4} k m / m i n$
Speed in $k m / h r = \frac{3}{4} \times \frac{k m}{m i n} \times \frac{60 m i n}{h r} = (15 \times 3) k m / h r = 45 k m / h r$ .