The oil drop experiment by R.A. Millikan was performed to find________.

charge on the neutron

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charge on the electron

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charge on the Proton

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None of these

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Solution

The correct option is B charge on the electron
The oil drop experiment was performed by R.A. Millikan in order to determine the charge and charge/mass ratio of electrons. Thus correct answer is option B.

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Similar questions

Q. Assume that Millikan performed the oil drop experiment. In the oil drop experiment, the following charges(in arbitrary units) were found on a series of oil droplets. Calculate the magnitude of the charge on the electron.
(a) 1.6 × 10-¹9 C
(b) 4 × 10-¹5 C
(c) 2 × 10-¹9C
(d) 2 × 10-¹5 C

Assume that Millikan performed the oil drop experiment. In the oil drop experiment, the following charges(in arbitrary units) were found on a series of oil droplets.

The data obtained is as follows:

2 $\times$ $10^{- 19}$ C
4 $\times$ $10^{- 19}$ C
6 $\times$ $10^{- 19}$ C

Calculate the magnitude of the charge on the electron.

Q. If

g_{E}

and

g_{M}

are the accelerations due to gravity on the surfaces of the earth and moon respectively and if Milikan's oil drop experiment could be performed on the two surfaces, one will find the ratio

\frac{electronic charge on the moon}{electronic charge on the earth}

to be:

(What Millikan did was to put a charge on a tiny drop of oil, and measure how strong an applied electric field had to be in order to stop the oil drop from falling.)

Q. The oil drop experiment by R.A. Mulliken was performed to find :

Q. Why are electrons attached to the oil drops in Millikan experiment?

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The oil drop experiment by R.A. Millikan was performed to find________.

The correct option is B charge on the electronThe oil drop experiment was performed by R.A. Millikan in order to determine the charge and charge/mass ratio of electrons. Thus correct answer is option B.

The correct option is B charge on the electron
The oil drop experiment was performed by R.A. Millikan in order to determine the charge and charge/mass ratio of electrons. Thus correct answer is option B.