The one dimensional heat conduction partial differential rquation ∂T∂t=∂2T∂x2, is
A
Parabolic
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Hyperbolic
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Elliptic
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Mixed
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A Parabolic ∂T∂t=∂2T∂x2 ........ (i)
Comparing (i) with A∂2T∂x2+B∂2T∂x∂y+C∂2T∂y2+2G∂T∂x+2F∂T∂y+H=0 A=1,B=0,C=0 ∵B2−4AC=0 ⇒ Parabolic Partial Differential Equation