The one's digit of a two digit number is double the digit the tens place. If the sum of the digits is $9$ . Find the number

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Solution

Let $x$ be the ten's digit.
One's digit $= 2 x$
Required number $= x \times 10 + 2 x$
Also,
$x + 2 x = 9$
$\Rightarrow x = \frac{9}{3} = 3$
Therefore,
Required number $= 3 \times 10 + 2 \times 3 = 30 = 6 = 36$
Hence the required number is $36$ .

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The one's digit of a two digit number is double the digit the tens place. If the sum of the digits is 9. Find the number

Let x be the ten's digit.One's digit =2xRequired number =x×10+2xAlso,x+2x=9⇒x=93=3Therefore,Required number =3×10+2×3=30=6=36Hence the required number is 36.

The one's digit of a two digit number is double the digit the tens place. If the sum of the digits is $9$ . Find the number

Let $x$ be the ten's digit.
One's digit $= 2 x$
Required number $= x \times 10 + 2 x$
Also,
$x + 2 x = 9$
$\Rightarrow x = \frac{9}{3} = 3$
Therefore,
Required number $= 3 \times 10 + 2 \times 3 = 30 = 6 = 36$
Hence the required number is $36$ .