The One's Digit in the Square of 77 is:
The square of '77‘ is ’5929‘. The One’s digit in ’5929‘ is ’9'.
Therefore, one’s digit in the square of '77‘ is ’9'
Write 3-digit numbers ending with 0, 1, 4, 5, 6, 9, one for each digit, but none of them is a perfect square.
if 5x is in tens digit and 2x is in ones digit find the number=---
options- 8x,53x,15x square,53x square