You visited us 1 times! Enjoying our articles? Unlock Full Access!

Oxidation Number Method

The only cati...

Question

The only cations present in a slightly acidic solution are $F e^{3 +}, Z n^{2 +} a n d C u^{2 +}$ . The reagent, added in excess to this solution, that would identify and separate $F e^{3 +}$ in one step is:

2MHCl

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6M NH₃

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6M NaOH

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H₂S(gas)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
6M NH₃

$F e^{3 +} d i l . N H_{3} - ---- \to e x c e s s F e (O H)_{3} ↓ p p t Z n^{2 +} d i l . N H_{3} - ---- \to e x c e s s [Z n (N H_{3})_{4}]^{2 +} C u^{2 +} d i l . N H_{3} - ---- \to e x c e s s [C u (N H_{3})_{4}]^{2 +}$

Suggest Corrections

Similar questions

Q. The only cations present in a slightly acidic solutio are

F e^{3 +}, Z n^{2 +}

and

C u^{2 +}

. The reagent that when added in excess to this solution would identify and separate

F e^{3 +}

in one step is :

The only cations present in a slightly acidic solution are $F e^{3 +}, Z n^{2 +}$ and $C u^{2 +}$ . The reagent that when added in excess of this solution would identify and separate $F e^{3 +}$ in one step is:

Q. The only cations present in a slightiy acidic solution are

F e^{3 +}

Z n^{2 +}

and

C u^{2 +}

The reagent that when added in excess to this solution would identify and separate

F e^{3 +}

in one step is :

Q. The only cations present in a slightly acidic solution are

F e^{3 +}

Z n^{2 +}

and

C u^{2 +}

. The reagent which when added in excess to this solution would identify the

F e^{3 +}

ion in one step is :

Q. On passing

H_{2} S

into a solution containing both

Z n^{2 -}

and

C u^{2 -}

in acidic medium, only CuS gets precipitated. This is because :

Join BYJU'S Learning Program

The only cations present in a slightly acidic solution areFe3+,Zn2+ and Cu2+. The reagent, added in excess to this solution, that would identify and separate Fe3+ in one step is:

The correct option is B 6M NH3 Fe3+dil.NH3−−−−−→excessFe(OH)3 ↓ pptZn2+dil.NH3−−−−−→excess[Zn(NH3)4]2+Cu2+dil.NH3−−−−−→excess[Cu(NH3)4]2+

The only cations present in a slightly acidic solution are $F e^{3 +}, Z n^{2 +} a n d C u^{2 +}$ . The reagent, added in excess to this solution, that would identify and separate $F e^{3 +}$ in one step is:

The correct option is B
6M NH₃

$F e^{3 +} d i l . N H_{3} - ---- \to e x c e s s F e (O H)_{3} ↓ p p t Z n^{2 +} d i l . N H_{3} - ---- \to e x c e s s [Z n (N H_{3})_{4}]^{2 +} C u^{2 +} d i l . N H_{3} - ---- \to e x c e s s [C u (N H_{3})_{4}]^{2 +}$