The only CORRECT combination that gives two different carboxylic acids is
A
(II) (iv) (R)
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B
(III) (iii) (P)
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C
(I) (i) (S)
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D
(IV) (iii) (Q)
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Solution
The correct option is A (III) (iii) (P) The only CORRECT combination that gives two different carboxylic acids is (III) benzaldehyde (iii) (CH3CO)2O/CH3COOK (P) condensation. It is an example of perkin condensation. Two isomers cis and trans corresponds to two carboxylic acids (Z) and (E) 3-phenylacrylic acid.