The only statement among the following that is a tautology is
A
b→[a∧(a→b)]
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B
a∧(a∨b)
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C
a∨(a∧b)
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D
[a∧(a→b)]→b
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Solution
The correct option is D[a∧(a→b)]→b aba∨ba∧ba∧(a∨b)a∨(a∧b)a→ba∧(a→b)a∧(a→b)→bb→a∧(a→b))TTTTTTTTTTTFTFFTFFTTFTTFFFTFTFFFFFFFTFTT ∵ The truth value of all the elements of the column a∧(a→b)→b are true. ∴a∧(a→b)→b is a tautology