The open loop transfer fucntion of a unity feedback system is G(s)=k(s+2)(s+1+j1)(s+1−j1).
The root locus plot of the system has
A
two breakaway points located at s = -0.59
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B
one breakaway point located at s =-0.59
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C
one breakaway point located at s =-3.41
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D
one breakaway point located at s =-1.41
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Solution
The correct option is C one breakaway point located at s =-3.41
R.L → Root locus part
NRL → Not root locus part G(s)H(s)=K(s+2)s2+2s+2
For the break-away point dG(s)H(s)ds=0 K(s2+2s+1)1−K(s+2)(2s+2)(s2+2s+2)2=0
Solving this we get s2+4s+2=0 s=−4±2√22=−2±√2 s=−3.414,−0.59
From the root locus part it is obvious that the valid break away point = -3.424