Question

The opposite angles of a parallelogram are $(3x-2{)}^{\circ }$ and $(x+48{)}^{\circ }$. What is the value of $x$?

• A. 25

Answer 1

The correct option is A 25
In a parallelogram, opposite angles are equal.

$\therefore (3x-2{)}^{\circ }=(x+48{)}^{\circ }\Rightarrow 3x-x={48}^{\circ }+2^{\circ }\Rightarrow 2x={50}^{\circ }\Rightarrow x=\frac{50}{2}\therefore x=25°$

$\text{Hence, the required value of}x\text{is}{25}^{\circ }.$