Question

The opposite pairs of sides of a square are increased by $40$% and $30$% respectively. The area of the resulting rectangle exceeds the area of the square by

• A. $42$%
• B. $62$%
• C. $82$%
• D. $72$%

Answer 1

The correct option is C $82$%

Let side of square be $10$ units, then area of square = $10\times 10=100$ sq.units

Now, length $=10+40\%$ of $10=14$

Breadth $=10+30\%$ of $10=13$

Area of rectangle formed = $14\times 13=182$

% increase in area = $\frac{182\times 100}{100}\times 100=82$%