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Standard XII

Biology

Pyranose and Furanose

The optical r...

Question

The optical rotation of the $α$ form of pyranose is $+ {150.7}^{0}$ , that of the $β$ form is $+ {52.8}^{0}$ . In solution an equilibrium mixture of these anomers has an optical rotation of $+ {80.2}^{0}$ . The percentage of the $α$ - form in equilibrium mixture is:

28 %

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32 %

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68 %

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72 %

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Solution

The correct option is A $28 %$
Let the fraction of $α$ - form be $x$
therefore; ($+80.2^0) = x * (+150.7^0) + (1 - x)(52.8^o)$
$80.2 = 150.7 x + 52.8 - 52.8 x$
$80.2 = 97.9 x + 52.8$
$x = 0.2798$
The fraction form of $α$ - form is $0.2798$
Percentage of $α$ - form
$= 0.2798 * 100$
$= 27.98$ %
$= 28$ %

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The optical rotation of the α form of pyranose is +150.70, that of the β form is +52.80. In solution an equilibrium mixture of these anomers has an optical rotation of +80.20. The percentage of the α - form in equilibrium mixture is:

The correct option is A 28%Let the fraction of α - form be xtherefore; ($+80.2^0) = x * (+150.7^0) + (1 - x)(52.8^o)$80.2=150.7x+52.8−52.8x80.2=97.9x+52.8x=0.2798The fraction form of α- form is 0.2798Percentage of α- form =0.2798∗100=27.98%=28%

The optical rotation of the $α$ form of pyranose is $+ {150.7}^{0}$ , that of the $β$ form is $+ {52.8}^{0}$ . In solution an equilibrium mixture of these anomers has an optical rotation of $+ {80.2}^{0}$ . The percentage of the $α$ - form in equilibrium mixture is: