Question

The optimistic time $\left(t_o\right)$, most likely time $\left(t_m\right)$ and pessimistic time $\left(t_p\right)$ (in days) of the activities in the critical path of a network are given in the format $t_o-t_m-t_p$ in the figure below.


The expected completion time (in days) of the project is

• A. 42
• B. 35
• C. 33
• D. 40

Answer 1

The correct option is D 40

$(t_e{)}_{total}=(t_e{)}_{P\to Q}+(t_e{)}_{Q\to R}+(t_e{)}_{R\to S}+(t_e{)}_{S\to T}$

$=\frac{9+11\times 4+15}{6}+\frac{7+9\times 4+11}{6}+\frac{6+8\times 4+10}{6}+\frac{7+12\times 4+15}{6}$

$=\frac{34}{3}+9+8+\frac{35}{3}=40$ days