The orbit of geostationary satellite is circular. The time period of satellite depends on

mass of the Earth

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radius of the orbit

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height of the satellite from the surface of Earth

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All the above

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Solution

The correct option is D All the above
Time period of a satellite is given by $T = 2 π \sqrt{\frac{r^{3}}{G M_{e}}}$ , where $r = R_{e} + h$
Hence, it depends on mass of the Earth, radius of the orbit and height of the satellite from Earth's surface.

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The orbit of geostationary satellite is circular. The time period of satellite depends on

The correct option is D All the aboveTime period of a satellite is given by T=2π√r3GMe, where r=Re+hHence, it depends on mass of the Earth, radius of the orbit and height of the satellite from Earth's surface.

The correct option is D All the above
Time period of a satellite is given by $T = 2 π \sqrt{\frac{r^{3}}{G M_{e}}}$ , where $r = R_{e} + h$
Hence, it depends on mass of the Earth, radius of the orbit and height of the satellite from Earth's surface.