Question

The orbital angular momentum and angular momentum (classical analogue) for the electron of $4s$-orbital are respectively, equal to:

• A. $\sqrt{12}\frac{h}{2\pi }$ and $\frac{h}{2\pi }$
• B. Zero and $\frac{2h}{\pi }$
• C. $\sqrt{6}h$ and $\frac{2h}{\pi }$
• D. $\sqrt{2}\frac{h}{2\pi }$ and $\frac{3h}{2\pi }$

Answer 1

Answer: (B)

Zero and $\frac{2h}{\pi }$

Orbital angular momentum $=\sqrt{l(l+1)}\frac{h}{2\pi }$

$4S\Rightarrow l=0$

$=0$

Angular momentum $=\frac{nh}{2\pi }$

$4S\to n=4$ $=\frac{2h}{\pi }$