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Question

The orbital angular momentum and angular momentum (classical analogue) for the electron of $$4s$$-orbital are respectively, equal to:


A
12h2π and h2π
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B
Zero and 2hπ
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C
6h and 2hπ
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D
2h2π and 3h2π
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Solution

The correct option is A Zero and $$\dfrac { 2h }{ \pi } $$
Orbital angular momentum $$=\sqrt { l\left( l+1 \right)  } \cfrac { h }{ 2\pi } $$
$$4S\Rightarrow l=0$$
$$=0$$
Angular momentum $$=\cfrac{nh}{2\pi}$$
$$4S\rightarrow n=4$$  $$=\cfrac{2h}{\pi}$$

Chemistry

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