Question

The orbital angular momentum for an electron revolving in an orbit is given by $\sqrt{l(l+1)}\frac{h}{2\pi }$. What is the orbital angular momentum of an s-electron?

• A. 1
• B. 2
• C. 0
• D. 6

Answer 1

The correct option is C

0

For s-electron, I has a value of 0.
Thus, the momentum of s-election is $\sqrt{0(0+1)\frac{h}{2\pi }}=0$