Question

The orbital angular momentum of a 4d electron will be:

• A. $4\frac{h}{2\pi }$
• B. $\sqrt{6}\frac{h}{2\pi }$
• C. $\sqrt{6}\frac{h}{4\pi }$
• D. $\sqrt{2}\frac{h}{4\pi }$

Answer 1

The correct option is B $\sqrt{6}\frac{h}{2\pi }$

For d-orbital, $l=2$
where $l=$ Azimuthal quantum number

Orbital angular momentum is given by
$L=\frac{h}{2\pi }\sqrt{l(l+1)}$
Putting the value of $l$, we get
$L=\frac{h}{2\pi }\sqrt{2(2+1)}=\sqrt{6}\frac{h}{2\pi }$