Question

The orbital angular momentum of an electron in 2s orbital is,

• A. $+\frac{1}{2}$$\frac{h}{2\pi }$
• B. 0.0
• C. $\frac{h}{2\pi }$
• D. $\sqrt{2}$$\frac{h}{2\pi }$

Answer 1

The correct option is B 0.0

$l$ is azimuthal quantum number
$l$ = 0 $\to$ $s$ subshell
Orbital angular momentum = $\sqrt{l(l+1)}\hslash$
where $\hslash$ = $\frac{h}{2\pi }$
For 2$s$, $l$ = 0
Therefore, $\sqrt{l(l+1)}\hslash$ = 0