Question

The orbital angular momentum of an electron in $2s$ orbital is:

• A. $\frac{1}{2}\frac{h}{2\pi }$
• B. zero
• C. $\frac{h}{2\pi }$
• D. $\sqrt{2}\frac{h}{2\pi }$

Answer 1

Answer: (B)

zero

Angular momentum of electrons in an orbital is given by expression
$L=\sqrt{l(l+1)}\left(\frac{h}{2\pi }\right)$

where $l$ is Azimuthal quantum number.

$l=0$ for $s$ orbital.

$\therefore L=0$