Question

The orbital angular momentum of an electron in 2s-orbital is

• A. $+\frac{1}{2},\frac{h}{2\pi }$
• B. Zero
• C. $\frac{h}{2\pi }$
• D. $\sqrt{2},\frac{h}{2\pi }$

Answer 1

The correct option is B Zero

Expression for orbital angular momentum (L) is
$L=\sqrt{l(l+1)}\frac{h}{2\pi }=0$ for 2s - electrons
$\because$ For s - orbital, l = 0