Question

The orbital angular momentum of an electron in 2s orbitals is:

• A. $+\frac{1}{2}\frac{h}{2\pi }$
• B. zero
• C. $\frac{h}{2\pi }$
• D. $\sqrt{2}\frac{h}{2\pi }$

Answer 1

The correct option is B zero

We know that the expression for orbital angular momentum (L) is:

$L=\sqrt{l(l+1)}\frac{h}{2\pi }$

But for s-orbital, $l=0$ or the orbital angular momentum is zero.

Hence, the correct option is $B$