Question

The orbital angular momentum of an electron($l=1$) makes an angle ${45}^{\circ }$ from Z- axis. The $L_z$ of electron will be ($L_z=m\left(\frac{h}{2\pi }\right)$):

• A. $2\left(\frac{h}{2\pi }\right)$
• B. $0\left(\frac{h}{2\pi }\right)$
• C. $\frac{h}{2\pi }$
• D. $3\left(\frac{h}{2\pi }\right)$

Answer 1

Answer: (C)

$\frac{h}{2\pi }$

The orbital angular momentum of an electron ( $l=1$) makes an angle ${45}^{\circ }$ from Z- axis. The $L_z$ of electron will be $\frac{h}{2\pi }$.
As, $L_z=m\left(\frac{h}{2\pi }\right)$ and for ${45}^0$ angle $m=1$.