Question

The orbital angular momentum of an electron revolving in a p-orbital is :

• A. zero
• B. $\frac{h}{\sqrt{2}\pi }$
• C. $\frac{h}{2\pi }$
• D. $\frac{1}{2}\frac{h}{2\pi }$

Answer 1

The correct option is B $\frac{h}{\sqrt{2}\pi }$

The orbital angular momentum of an electron revolving in a p-orbital is:

$\sqrt{l(l+1)}\frac{h}{2\pi }=\sqrt{1(1+1)}\frac{h}{2\pi }=\frac{h}{\sqrt{2}\pi }$

Hence, option $B$ is correct.