The orbital diagram in which both Pauli's Exclusion principle and Hund's rule are violated is:

2s 2p

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2s 2p

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2s 2p

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2s 2p

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Solution

The correct option is D
2s 2p
Option (d) has two electrons with all the four quantum number same in the p orbitals. Hence it violates Pauli's exclusion principle.
It also violates Hund's rule of maximum multiplicity according to which electrons in a set of degenerate orbitals will not pair until all the orbitals has one electron each. Here one p orbital is empty.
Option (c) violates only Hund's rule.

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The strength of bonds formed by 2s - 2s, 2p - 2p and 2p - 2s overlap has the order:

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