The orbital overlapping is maximum in:

C l_{2}

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H I

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H C l

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H B r

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Solution

The correct option is A $C l_{2}$
$p - p$ overlapping is more effective compared to $s - p$ overlapping which is more effective than $s - s$ overlapping.

In ${C l}_{2}$ molecule, the bond is formed by $p - p$ overlapping. $H I, H C l$ and $H B r$ have $s - p$ overlapping.

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