The orbital radius of the first excited level of positronium atom is
Note: $a_{0}$ is the orbital radius of ground state of hydrogen atom

4 a_{0}

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a_{0} / 2

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8 a_{0}

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2 a_{0}

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Solution

The correct option is B $8 a_{0}$
Given, electron in the positronium has reduced mass $\frac{m_{e}}{2}$
And orbital radius of ground state of hydrogen atom is $a_{0}$ .
Therefore, for positronium, $r_{n} = 2 a_{0} n^{2}$
Hence, orbital radius of first excited level of positronium is $8 a_{0}$ .

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