Question

The orbital velocity is nearly 0.707 times that of escape velocity.

• A. True
• B. False

Answer 1

The correct option is A True

We know that $v_{escape}=\sqrt{2}\times v_{orbital}$

$\Rightarrow v_{orbital}=\frac{v_{escape}}{\sqrt{2}}=0.707\times v_{escape}$

Hence the given statement is true and correct answer is option $A$