The orbital which is not involved in the hybridization of the central atom in ICl−4is
A
dz2
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B
Dx2−y2
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C
dxy
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D
s
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Solution
The correct option is Cdxy
Solution:
First we need to know the hybridization of ICl−4, which is sp3d2
So here 2d−orbitals are used in this complex formation.
We must know the splitting of d orbitals is as per above shown image:
So first two orbitals d(z)2 and d(X2−y2) are filled then remaining 3 orbitals are filled. As per the hybridization of ICl−4, which is sp3d22 d orbitals are filled which must be d(z)2 and d(X2−y2).
So dxy is not involved here, Option C is correct answer