Question

The orbital which is not involved in the hybridization of the central atom in $IC{l}_4^{-}$is

• A. $d_{z^2}$
• B. $D_{x^2-y^2}$
• C. $d_{xy}$
• D. $s$

Answer 1

The correct option is C $d_{xy}$

Solution:

First we need to know the hybridization of $IC{l}_4^{-}$, which is $s{p}^3{d}^2$

So here $2$ $d-orbitals$ are used in this complex formation.

We must know the splitting of $d$ orbitals is as per above shown image:

So first two orbitals $d_{(}z{)}^2$ and $d_{(}{X}^2-y^2)$ are filled then remaining $3$ orbitals are filled. As per the hybridization of $IC{l}_4^{-}$, which is $s{p}^3{d}^2$ $2$ d orbitals are filled which must be $d_{(}z{)}^2$ and $d_{(}{X}^2-y^2)$.

So $d_{xy}$ is not involved here, Option C is correct answer