Question

The order and degree of differential equation $[1+{\left(\frac{dy}{dx}\right)}^2]=\frac{d^{2}y}{d{x}^2}$ are
a) $2,\frac{3}{2}$
b) 2, 3
c) 2, 1
d) 3, 4

Answer 1

Given that $[1+{\left(\frac{dy}{dx}\right)}^2]=\frac{d^{2}y}{d{x}^2}$
$\therefore$ order = 2 and degree =1