The order and degree of - d2ydx2- dydx2 -1-2-d3ydx3 is-

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Order of a Differential Equation

The order and...

Question

The order and degree of ${[\frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{2}]}^{1 / 2} = \frac{d^{3} y}{d x^{3}}$ is:

1,2

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3,1

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3,2

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2,4

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Solution

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\frac{d^{2} y}{d x^{2}} + {(1 + (\frac{d y}{d x}))}^{3 / 2} = 0

{[2 \frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{2}]}^{3 / 2} = (\frac{d^{3} y}{d x^{3}})

m

n

{(\frac{d^{2} y}{d x^{2}})}^{5} + 4 \frac{(\frac{d^{2} y}{d x^{2}})}{(\frac{d^{3} y}{d x^{3}})} + (\frac{d^{3} y}{d x^{3}}) = x^{2} - 1

(m, n) =

y = 1 + {(\frac{d y}{d x})}^{1} + \frac{1}{2!} {(\frac{d y}{d x})}^{2} + \frac{1}{3!} {(\frac{d y}{d x})}^{3} + . . . . .

\frac{d^{2} y}{d x^{2}} = x l o g (\frac{d y}{d x})

{[1 + {(\frac{d y}{d x})}^{2}]}^{5 / 2} = \frac{d^{3} y}{{d x}^{3}}

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