The order and degree of dydx 3-5x- d2ydx2 3-2 is-

The correct option is D 2,3 y_1^3+5x=y_2^3/2 ⇒ (5x+y_1^3)^2=y_2^3 ⇒ order=2 degree=3 ...

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Degree of a Differential Equations

The order and...

Question

The order and degree of ${(\frac{d y}{d x})}^{3} + 5 x = {(\frac{d^{2} y}{d x^{2}})}^{3 / 2}$ is:

2,3

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2,2

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1,3

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1,2

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\sqrt{1 + {(\frac{d^{2} y}{d x^{2}})}^{3}} = {(2 + \frac{d y}{d x})}^{1 / 3}

\frac{d^{3} y}{d x^{3}} + {(\frac{d^{2} y}{d x^{2}})}^{3} + \frac{d y}{d x} = x y

{[\frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{2}]}^{1 / 2} = \frac{d^{3} y}{d x^{3}}

m

n

{(\frac{d^{2} y}{d x^{2}})}^{5} + 4. \frac{{(\frac{d^{2} y}{d x^{2}})}^{3}}{(\frac{d^{3} y}{d x^{3}})} + (\frac{d^{3} y}{d x^{3}}) = x^{2} - 1

(\frac{d^{2} y}{d x^{2}})^{3} = x y + (\frac{d y}{d x})^{3}

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