The order and degree of the differential equation [1+(dydx)2]3=ρ2[d2ydx2]2 are respectively.
A
3 and 2
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B
2 and 2
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C
2 and 3
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D
1 and 3
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Solution
The correct option is B2 and 2 Order of a differential equation is the order of the highest derivative present in it and degree is the highest power of the highest order derivative.
Thus, in the given equation, order = 2 and degree = 2. ⎛⎝[d2ydx2]2⎞⎠