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Question

The order and degree of the differential equation [2d2ydx2+(dydx)2]3/2=(d3ydx3) are respectively

A
2 and 2
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B
2 and 1
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C
3 and 2
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D
3 and 3
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E
2 and 4
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Solution

The correct option is C 3 and 2
Given, [2d2ydx2+(dydx)2]3/2=d3ydx3
On squaring both sides, we get
[2d2ydx2+(dydx)2]3=(d3ydx3)2
Hence, order is 3 and degree is 2.

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