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Question

The order and degree of the differential equation

⎡⎢ ⎢⎣{x−(dydx)2}32⎤⎥ ⎥⎦2=(a2d2ydx2)

A
2,1
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B
1,2
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C
2,2
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D
1,1
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Solution

The correct option is A 2,1
Given,
⎢ ⎢{x(dydx)2}32⎥ ⎥2=(a2d2ydx2)
The above differential equation can be written as
{x(dydx)2}3=(a2d2ydx2)
It is clear that second order derivative terms are involved in the equation which is the highest order derivative term in the equation so order of the differential equation is 2 and its power is 1. So degree is 1.

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