The order and degree of the differential equation -1 - dydx 2 - -d2ydx2 23 is

The correct option is A 2,3 Given, √(1+ ( dydx )^2)= ( d^2ydx^2 )^3/2 squaring on both sides, we get 1+ ( dydx )^2= ( d^2ydx^2 )^3 Therefore, order ...

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Standard XII

Mathematics

Chain Rule of Differentiation

The order and...

Question

The order and degree of the differential equation $\sqrt{1 + {(\frac{d y}{d x})}^{2}} = {(] \frac{d^{2} y}{d x^{2}})}^{\frac{2}{3}}$ is

2, 3

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3, 2

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1, 2

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2, 2

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Solution

The correct option is A $2, 3$
Given,

$\sqrt{1 + {(\frac{d y}{d x})}^{2}} = {(\frac{d^{2} y}{d x^{2}})}^{\frac{3}{2}}$

squaring on both sides, we get

$1 + {(\frac{d y}{d x})}^{2} = {(\frac{d^{2} y}{d x^{2}})}^{3}$

Therefore, order 2, degree 3.

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The order and degree of the differential equation √1+(dydx)2=(]d2ydx2)23 is

The correct option is A 2,3Given,√1+(dydx)2=(d2ydx2)32squaring on both sides, we get1+(dydx)2=(d2ydx2)3Therefore, order 2, degree 3.

The order and degree of the differential equation $\sqrt{1 + {(\frac{d y}{d x})}^{2}} = {(] \frac{d^{2} y}{d x^{2}})}^{\frac{2}{3}}$ is

The correct option is A $2, 3$
Given,

$\sqrt{1 + {(\frac{d y}{d x})}^{2}} = {(\frac{d^{2} y}{d x^{2}})}^{\frac{3}{2}}$

squaring on both sides, we get

$1 + {(\frac{d y}{d x})}^{2} = {(\frac{d^{2} y}{d x^{2}})}^{3}$

Therefore, order 2, degree 3.