The order and degree of the differential equation √dydx−4dydx−7x=0 are
A
1 and 1/2
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B
2 and 1
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C
1 and 1
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D
1 and 2
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Solution
The correct option is D1 and 2 Given equation is √dydx−4dydx−7x=0 ⇒dydx=16(dydx)2+49x2+56xdydx Obviously, it is first order and second degree differential equation.