The order and degree of the following differential equation [1+(dydx)2]5/2=d3ydx3 are respectively
A
3,2
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B
3,10
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C
2,3
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D
3,5
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Solution
The correct option is A3,2 Given differential equation is [1+(dydx)2]5/2=d3ydx3 ⇒(d3ydx3)2=[1+(dydx)2]5 From above it is clear that the order and degree of the given differetial equation are 3 and 2 respectively.