The order and degree of x-d3y-dx2-1- dy-dx4 is

The correct option is A 3, 2 x√(1 y_1^4)=y_3 ⇒ x^2(1 y_1^4)=y_3^2 ⇒ Order= 3 Degree= 2 ...

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Order of a Differential Equation

The order and...

Question

The order and degree of $x = \frac{\frac{d^{3} y}{d x^{2}}}{\sqrt{1 - {(\frac{d y}{d x})}^{4}}}$ is

1, 4

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4, 3

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3, 2

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3, 4

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{[\frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{2}]}^{1 / 2} = \frac{d^{3} y}{d x^{3}}

{(\frac{d^{3} y}{d x^{3}})}^{2} + {(\frac{d^{2} y}{d x^{2}})}^{3} + {(\frac{d y}{d x})}^{4} + y^{5} = 0

\frac{d^{4} y}{d x^{4}} + (\frac{d^{3} y}{d x^{3}})^{2} + (\frac{d^{2} y}{d x^{2}})^{3} + (\frac{d y}{d x})^{4} = 0

\frac{d^{2} y}{d x^{2}} = \sqrt[3]{1 - {(\frac{d y}{d x})}^{4}}

\frac{d^{4} y}{d x^{4}} + (\frac{d^{3} y}{d x^{3}})^{2} + (\frac{d^{2} y}{d x^{2}})^{3} + (\frac{d y}{d x})^{4} = 0

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