Question

The order, degree of the differential equation of all circles of radius r, having centre only axis passing through the origin is (where $r$ is arbitrary constant)

• A. $1,1$
• B. $2,1$
• C. $3,1$
• D. $4,2$

Answer 1

The correct option is A $1,1$

Now as center is the origin, equation will be

$x^2+y^2=r^2$

By differentiating, we get

$2x+2y\frac{dy}{dx}=0$

$\frac{dy}{dx}=\frac{-x}{y}$

Degree=1, Order=1.